Help with Algebra 2??
yes, what do you need help?
\(\large\color{slate}{ x=\sqrt{3x+10} }\) to start, raise each side to the second power.
\(\large\color{slate}{ \color{red}{(}x\color{red}{)^2}=\color{red}{(}\sqrt{3x+10}\color{red}{)^2} }\)
tell me, what do you get after doing this?
x^2=3x+10?
yes.
Now, I would subtract 3x, and then 10, from both sides. Then I would factor both sides.
I mean factor the left side, not both sides. Sorry.
\(\large\color{slate}{ x^2=3x+10 }\) will do a shortcut, subtracting the entire \(\large\color{slate}{ \color{blue}{3x+10} }\) from both sides, \(\large\color{slate}{ x^2\color{blue}{-3x-10}=3x+10 \color{blue}{-3x-10}}\)
what do you get after doing this?
lost?`
nello, if you are lost please reply, don't hesitate....
yeah... sorry
Sure, sure.... no need for being sorry. Lets see, do you understand how we got till \(\large\color{slate}{ x^2=3x+10 }\) ?
we squared each side?
yes, exactly!
Now, lets go ahead and subtract 3x from both sides. \(\large\color{slate}{ x^2\color{blue}{-3x}=3x+10 \color{blue}{-3x}}\) can you tell me what we get after doing this?
now what do I do? should I get the x on one side?
tell me what cancels on the right side (if anything) ?
the 10
the 10 stands there
\(\large\color{slate}{ x^2\color{blue}{-3x}=\color{black}{\cancel {3x}}+10 \color{blue}{\cancel{-3x}}}\)
then the 3?
3x, you mean?
yeah
so now its x^-3x=10
x^2
yes, \(\large\color{slate}{ x^2-3x=10 }\)
\(\large\color{slate}{ x^2-3x=10 }\) subtract 10 from both sides, you get? \(\large\color{slate}{ x^2-3x\color{blue}{-10}=10 \color{blue}{-10}}\)
If I can get 10 to the left too I can factor them and the answer will be 5 and -2?
yes, very good x=-2 or x=5.
but we must check them
\(\large\color{slate}{ x=\sqrt{3x+10}}\) True/False: 1. \(\large\color{slate}{ 5=\sqrt{3(5)+10}}\) 2. \(\large\color{slate}{ -2=\sqrt{3(-2)+10}}\)
can you answer this question?
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