HELP PLEASE!!! Perform the following operations and prove closure.
\[\frac{ x }{ x + 3 } + \frac{ x + 2 }{ x +5 }\]
@Directrix
@ganeshie8
it says "A rational expression is a ratio of two polynomials—a fraction whose numerator and denominator are polynomials. Just as addition, subtraction, and multiplication are closed on integers, they are closed for rational expressions as well, with the addition of division since the division of rational expressions also yields a rational expression."
@Directrix
I believe if you can show that a/b + c/d = (ad + bc) / (bd), then you've proven that this rational expression is closed under addition.
so x/x+3 + x+2/x+5 = (x)(x+5) + (x+3)(x+2)/(x+3)(x+5)
close, 2(x^2 + 5x + 3) / (x+3)(x + 5)
what's the 2?
when you're doing the math to get a common denominator, you end up having to factor out a 2
wait I'm so confused can you do what you did but with the equation thing so I can se better
equation thing?
like where it says at the bottom next to draw
I did cross multiplication and I got \[\frac{ x ^{2} + 5x}{ x ^{2} + 2x + 3x + 6}\] then, \[\frac{ x ^{2} + 5x}{ x ^{2} + 5x + 6}\]
x/x+3 + x+2/x+5 = (x)(x+5) + (x+3)(x+2) is what you end up with according to the formula expand (x + 3)(x + 2) out x^2 + 5x + 6 x^2 + 5x + x^2 + 5x + 6 is what you end up with on top simplify it 2x^2 + 10x + 6 factor out the 2 2(x^2 + 5x + 3) on top
ooohh ok I see what did wrong.
then what about the bottom?
the bottom just stays (x + 3)(x + 5)
do you have to distribute?
if by distribute you mean expand it, then you would get x^2 + 8x + 15, which doesn't really do anything, so you would just leave it alone.
ok so the answer is \[\frac{ 2(x ^{2} + 5x + 3) }{ (x + 3)(x + 5) }\]
yup, and since you can write it in this form, then you've shown that this rational expression is closed under addition if x is an integer
and not -3 or -5
ok thanks can you help with three more questions? please.
yeah
ok I'm gonna start a new question
you dont have to
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