Question

Can someone check my work? Solving the triangle

Answer 1

Given:
B = 73 degrees
b = 15
c = 8
\(\sf\dfrac{sin(73)}{15}~=~\dfrac{sin(x)}{8}\)

Answer 2

\(\sf\dfrac{8sin(73)}{15}~=~sin(x)\)

Answer 3

\(\sf arcsin(\dfrac{8sin(73)}{15})\)

Answer 4

what woule be \(\sin(C)\) right?

Answer 5

Yes, I am using x in place of C

Answer 6

Then I got C = 30.7, angle A = 25.8

Answer 7

use C so as you know which angle it is
not that the variable is important, but it is good go label angles opposite sides by the capital letter

Answer 8

\(\sf\dfrac{15}{sin(30.7)}~=~\dfrac{A}{sin(76.3)}\)

Answer 9

\[30.7\] looks good to me

Answer 10

\(\sf\dfrac{15sin(76.3)}{sin(30.7)}=A\)

Answer 11

Ah, I used A instead of a, but hopefully you know what I mean xD

Answer 12

And finally a = 28.5

Answer 13

i am lost
what is angle A?

Answer 14

Oh whoops, I got 76.3 for angle A

Answer 15

oh i see it is \(76.3\) which you used, but for some reason above you said \(A=25.8\)

Answer 16

oh i see \(a=23.8\)

Answer 17

rather a = 25.8

Answer 18

Oh, I think I was looking at the wrong problem above hah

Answer 19

i get something different for A
http://www.wolframalpha.com/input/?i=15sin%2876.3%29%2Fsin%2873%29

Answer 20

Why over sin(73)?

Answer 21

Oh, you were using b and B

Answer 22

B=73
b=15

Answer 23

Why do I get a different answer when using c and C though?