Question

thanks!

Answer 1

@ganeshie8

Answer 2

\[\left(\frac{g}{f}\right)(-2)\]

like this ?

Answer 3

yes

Answer 4

\[\left(\frac{g}{f}\right)(-2) = \dfrac{g(-2)}{f(-2)}\]

Answer 5

find the values of g(-2) and f(-2)
then plug them above and simplify

Answer 6

\(g(x) = x^2+2\)

\(g(-2) = ?\)

Answer 7

-2^2+2

Answer 8

=-2

Answer 9

do you mean : g(-2) = (-2)^2 + 2 ?

Answer 10

that simplifies to 4 + 2 which equals 6

Answer 11

yes and yes

Answer 12

good, so you have g(-2) = 6
save it

Answer 13

go ahead and find f(-2) similarly

Answer 14

\(f(x) = x-2\)

\(f(-2) = ?\)

Answer 15

(-2)-2?

Answer 16

Yes, simplify

Answer 17

-4

Answer 18

plug them in
\[\left(\frac{g}{f}\right)(-2) = \dfrac{g(-2)}{f(-2)} = ?\]

Answer 19

(6/-4)

Answer 20

yes, simplify\[\left(\frac{g}{f}\right)(-2) = \dfrac{g(-2)}{f(-2)} = \dfrac{6}{-4} = ?\]

Answer 21

looks you can cancel 2 in both numerator and denominator

Answer 22

-3/4

Answer 23

-3/2

Answer 24

Correct ! good job !

Answer 25

thanks to you

Answer 26

\[\left(\frac{g}{f}\right)(-2) = \dfrac{g(-2)}{f(-2)} = \dfrac{6}{-4} = -\dfrac{3}{2}\]

Answer 27

yw