PLEASE HELP WILL GIVE MEDAL AND FAN!!<3 What is the length x?
HI!!
Hello!! (:
this looks like a big drag, but i bet we can do it we have to find a couple lengths first
haha ok
my draw tool is not working you have one triangle on the bottom , the right triangle with both sides one you see the one i mean?
yeah i see it
|dw:1421988445493:dw|
finally ok by pythagoras the length of the hypotenuse is \(\sqrt2\)
now we move on to the next triangle
alright
the one in the middle right?
|dw:1421988553618:dw|yea that one
one leg is \(\sqrt2\) the other is 1 so pythagoras again for the hypotenuse \[\sqrt{\sqrt2^2+1^2}=\sqrt{2+1}=\sqrt3\]
one more to go!
okay haha(:
but now we don't bother drawing it one leg is \(\sqrt3\) the other is 1, pythagoras for the last time gives \[\sqrt{\sqrt3^2+1^2}=\sqrt{3+1}=\sqrt4\]
better known as \(\huge \color\magenta2\)
so is that the answer? or you just did the square root of 4
lol "nutellia"
yeah final answer is 2, since the square root of four is 2
haha yup thats what they call me /.\ lol and thank you so much! you were really nice and helpful(:
your welcome darling \(\color\magenta\heartsuit\)
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