Question

having a homework problem... what is the daughter nucleus produced when 213Bi undergoes alpha decay... i came up with the answer 20581Ti.. is that correct

Answer 1

Almost but not quite. Remember \(\alpha\)-decay is the emission of a \(^{4}_{2}\sf He\) particle.
So the general formula is:\[\Large ^{a}_{b}\sf X \rightarrow ^{a-4}_{b-2}Y+_{2}^{4}He\]
In your case we have:\[\large _{83}^{213} \sf Bi \rightarrow _{83-2}^{213-4} \it Y \sf + _{2}^{4}He\]
The isotope created become:
\[\Large _{81}^{209}\sf Ti\]

Answer 2

thanks i figured it out before i got to check your response