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An object moves in a straight line so that after t seconds, it is t^3 +t^2 +6t feet from its starting point.
Find the distance the object travels between the times t=2 and t=x.
Could you please explain how to get the answer?

Question

Please help! Fan and medal!
An object moves in a straight line so that after t seconds, it is t^3 +t^2 +6t feet from its starting point.
Find the distance the object travels between the times t=2 and t=x.
Could you please explain how to get the answer?

anonymous · Answer

I think the answer is (24) - (x^3 +x^2 +6x) bur im not sure if its right

loser66 · Answer

put absolute value in

loser66 · Answer

I mean $|24-(x^3+x^2+6x)|$

loser66 · Answer

in case t < 2 seconds, the expression still holds

anonymous · Answer

@Loser66 thank you :)

perl · Answer

it turns out that the original function is always increasing, and is positive for t > 2 . 
therefore we can integrate it the position function