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Chemistry 60 Online
OpenStudy (anonymous):

What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4? A. 0.0001M CuSO4 B. 2.79M CuSO4 C. 0.109M CuSO4 D. 9.66M CuSO4

OpenStudy (anonymous):

@JoannaBlackwelder

OpenStudy (joannablackwelder):

Any ideas on how to start? Do you know what molarity is?

OpenStudy (anonymous):

I'm not going to lie to you, when numbers come into play with science, i get very confused. So, im not really that sure the correct way to start..

OpenStudy (joannablackwelder):

Ok, no worries. \[Molarity = \frac{ Moles Solute }{ LiterSolution }\]

OpenStudy (joannablackwelder):

Can you find how many liters of solution we have?

OpenStudy (anonymous):

So, are you dividing 974 by 17?

OpenStudy (joannablackwelder):

No...we are given that we have 974 mL, so we need to convert that to liters.

OpenStudy (joannablackwelder):

Since there are 1000 mL in a Liter, we have .974 L.

OpenStudy (joannablackwelder):

Make sense so far?

OpenStudy (anonymous):

Yes it does

OpenStudy (joannablackwelder):

:D

OpenStudy (joannablackwelder):

Then we need to calculate the moles of CuSO4.

OpenStudy (joannablackwelder):

We do that by starting with the grams we are given, and find the molar mass from the periodic table to convert to moles.

OpenStudy (joannablackwelder):

Do you know how to do that?

OpenStudy (anonymous):

I'm trying to lol

OpenStudy (joannablackwelder):

:) Ok. Let me know what you get.

OpenStudy (anonymous):

Whats the compound or element I need to convert? Lol

OpenStudy (joannablackwelder):

CuSO4

OpenStudy (joannablackwelder):

From grams to moles :D

OpenStudy (anonymous):

The molar mass is 159.6086 correct?

OpenStudy (joannablackwelder):

Yes, great!

OpenStudy (anonymous):

The correct answer is between A and C right? I can automatically rule out B and D?

OpenStudy (joannablackwelder):

Sorry, just a minute.

OpenStudy (anonymous):

Okay. because i converted the 17 grams into moles and I got 0.10651055143653..

OpenStudy (anonymous):

The answer I am thinking is C

OpenStudy (joannablackwelder):

Yep, I get C too! :D

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