Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A (n) = -3 + (n – 1)(-2.2)

A) -3, -11.8, -25
B) 0, -6.6, -19.8
C) -3, -9.6, -22.8
D) -2.2, -11.8, -19.8

Answer 1

@studygeek15

Answer 2

Just put in 1, 4 and 10 one by one instead of n

Answer 3

A (1) = -3 + (1 - 1)(-2.2) @ArsalanAijaz

Answer 4

Do what @ArsalanAijaz said.
For the first one
A (1) = -3 + (1 – 1)(-2.2) and solve.

Answer 5

Aye sir :P

Answer 6

No for the first one.
A (1) = -3 + (1 – 1)(-2.2)
= -3 + (0)(-2.2)
= -3 + 0
= -3
Remember that anything times 0 is equal to 0

Answer 7

Do the same thing for 4. Let me know what number you get.

Answer 8

A (n) = -3 + (n – 1)(-2.2)

A (4) = -3 + (4-1)(-2.2)
= -3 + (3)(-2.2)
= -3 + 6.6
= 9.6

Answer 9

Did I do that correct? @studygeek15

Answer 10

You have the right idea. 3 * -2.2 is -6.6 and add -3. Your number is correct, but you need a negative sign.

Answer 11

Oh okay, thank you

Answer 12

No problem.