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OpenStudy (bohotness):
OpenStudy (bohotness):
OpenStudy (anonymous):
ill try it. hold on.
OpenStudy (anonymous):
brb
OpenStudy (michele_laino):
Please note that you have to solve these, first:
\[4\;2/3=4+\frac{ 2 }{ 3 }=..,\quad2\;4/7=2+\frac{ 4 }{ 7 }=...\quad 7\;3/7=7+\frac{ 3 }{ 7 }=...\]
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OpenStudy (bohotness):
okay
OpenStudy (bohotness):
o.o
OpenStudy (bohotness):
;-; i dont understand
OpenStudy (chosenmatt):
agreed @Michele_Laino
OpenStudy (bohotness):
7.42857142857<-- what i got
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OpenStudy (michele_laino):
note that we have:
\[\left( \left( \frac{ 12 }{ 3 }+\frac{ 18 }{ 7 } \right)+\frac{ 52 }{ 7 } \right)=n+12\]
please note you should express your answer as a ratio, not a decimal number, so continue the expression above, plrase
OpenStudy (bohotness):
okay
OpenStudy (bohotness):
b?
OpenStudy (michele_laino):
oops, I have made an error it is 14/3 not 12/3,
so we have:
\[\left( \frac{ 14 }{ 3 }+\frac{ 18 }{ 7 } \right)+\frac{ 52 }{ 7 }=n+12\]
so what is
\[\frac{ 14 }{ 3 }+\frac{ 18 }{ 7 }=...\; ?\]
OpenStudy (bohotness):
wait 3 needs toi be that same as 7 need to find the lcd
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