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Mathematics 39 Online
OpenStudy (bohotness):

Solve for . A. B. C. D.

OpenStudy (bohotness):

OpenStudy (bohotness):

OpenStudy (anonymous):

ill try it. hold on.

OpenStudy (anonymous):

brb

OpenStudy (michele_laino):

Please note that you have to solve these, first: \[4\;2/3=4+\frac{ 2 }{ 3 }=..,\quad2\;4/7=2+\frac{ 4 }{ 7 }=...\quad 7\;3/7=7+\frac{ 3 }{ 7 }=...\]

OpenStudy (bohotness):

okay

OpenStudy (bohotness):

o.o

OpenStudy (bohotness):

;-; i dont understand

OpenStudy (chosenmatt):

agreed @Michele_Laino

OpenStudy (bohotness):

7.42857142857<-- what i got

OpenStudy (michele_laino):

note that we have: \[\left( \left( \frac{ 12 }{ 3 }+\frac{ 18 }{ 7 } \right)+\frac{ 52 }{ 7 } \right)=n+12\] please note you should express your answer as a ratio, not a decimal number, so continue the expression above, plrase

OpenStudy (bohotness):

okay

OpenStudy (bohotness):

b?

OpenStudy (michele_laino):

oops, I have made an error it is 14/3 not 12/3, so we have: \[\left( \frac{ 14 }{ 3 }+\frac{ 18 }{ 7 } \right)+\frac{ 52 }{ 7 }=n+12\] so what is \[\frac{ 14 }{ 3 }+\frac{ 18 }{ 7 }=...\; ?\]

OpenStudy (bohotness):

wait 3 needs toi be that same as 7 need to find the lcd

OpenStudy (michele_laino):

note that your lcd is 7*3

OpenStudy (bohotness):

okay 21

OpenStudy (michele_laino):

|dw:1422292140126:dw|

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