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Mathematics 12 Online
OpenStudy (anonymous):

The radioactive substance cesium-137 has a half-life of 30 years. The amount A(t) (in grams) of a sample of cesium-137 remaining after t years is given by the following exponential function. =A(t)266(1/2)^t/30 Find the initial amount in the sample and the amount remaining after 80 years. Round your answers to the nearest gram as necessary.

OpenStudy (anonymous):

i believe that u mean: A(t) = 266*(1/2)^(t/30), right?

OpenStudy (anonymous):

the initial amount is when t = 0, so just plug it in the equation above and find A(t=0). Now the amount after 80 years, juts plug t = 80 and find A(t=80).

OpenStudy (anonymous):

I got it! Thank you :-)

OpenStudy (anonymous):

Np

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