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Mathematics 10 Online
OpenStudy (anonymous):

two spherical chocolates are filled with a cream filling. the space inside one chocolate has a radius of 3 cm the other has a radius of 4.5 cm. how much more cream filling is in the larger chocolate than the smaller chocolate. estimate your answer to two decimal places @hartnn

OpenStudy (anonymous):

plz help

OpenStudy (phi):

do you know the formula for the volume of a sphere ?

OpenStudy (anonymous):

v= (4/3) * 3.14 * (radius ^ 3)

OpenStudy (phi):

this problem is asking you to find the volume of the big sphere (with radius 4.5) then find the volume of the smaller sphere (r=3) then subtract big - small to get how much bigger the big one than the small one. can you find the volume of the big sphere?

OpenStudy (anonymous):

381.51

OpenStudy (anonymous):

calculater helps

OpenStudy (phi):

ok but keep at least 3 decimals (because we will round to 2 decimals at the end)

OpenStudy (phi):

now do the same for the smaller sphere

OpenStudy (phi):

also, if you are using a calculator , use the "pi" key because it is more accurate than 3.14

OpenStudy (anonymous):

72 pi

OpenStudy (anonymous):

it says on question to use 3.14 to estimate so i do but because you say not to i wont

OpenStudy (phi):

if they say use 3.14 then you should use 3.14 but (unfortunately) they are being a bit stupid... you cannot get 2 decimals of accuracy if you start with only 2 decimals. using pi=3.14 you get 381.51 (as you found, and what we should use) but if we use pi=3.14159 we get 381.703 ...

OpenStudy (phi):

the answer should be 381.51 - 113.04

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

268.47

OpenStudy (phi):

yes.

OpenStudy (anonymous):

thank you

OpenStudy (phi):

be sure they really wanted you to use 3.14. otherwise, the answer would be 4/3 * pi * ( 4.5^3 - 3^3) = 268.606171881927 or approx 268.61 rounded to 2 decimal places

OpenStudy (anonymous):

thats what it says

OpenStudy (phi):

you might want to mention to your teacher that this question has a problem with it.

OpenStudy (anonymous):

i will

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