Question

@4Jesus

Answer 1

what is 99 to the 6th power?

Answer 2

941480149401

Answer 3

please note that:
\[99=3^{2}\cdot 11\]
so:
\[(99)^{6}=(3^{2}\cdot 11)^{6}=3^{12}\cdot 11^{6}\]

Answer 4

But \(3^{12}\times11^6\) is no better than \(99^6\) if you are doing it by hand. Maybe try \((100-1)^6\) and expand it using binomial theorem instead?