Sundar used linear combination to solve the system of equations shown. He did so by multiplying the first equation by 5 and the second equation by another number to eliminate the y-terms. What number did Sundar multiply the second equation by? @wio @iambatman @dtan5457 @Loser66
\(\begin{cases}2x+9y=41\\3x+5y=36\end{cases}\)
5*the first equation, that is 5*(2x +9y=41), show me what you get?
For x or y?
Can someone please help me finish this?
Multiply both sides by \(5\):\[ 2x +9y=41 \implies 5\times (2x +9y)=5\times (41)\implies 10x+45y=205 \]
You multiplied the top equation with the coefficient of \(y\) in the second equation: \[ 3x+\color{red}5y=36 \]So now you want to multiply the second equation with the coefficient of \(y\) in the top equation: \[ 2x+\color{red}9y=41 \]which is \(9\).
5?
So what do you get when you multiply the bottom equation by 9?
Do the equation? What's x? Or did you want me to multiply 41 and 9? @wio
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