Question

Which is a quadratic equation with a vertex of (4,-3_ and passes through point (6,2)?
The answer is y= 5/4 (x-4^2 -3 .. I know that h=4 ad k= -3
so idk how to get the 5/4, so i need to show the work

Answer 1

\[f(x)=a(x-4)-3\] solve for \(a\) by solving
\[f(6)=2=a(6-4)-3\]

Answer 2

you get
\[2=a(6-4)^2-3\]

Answer 3

whoa typos on the first two

Answer 4

\[f(x)=a(x-4)^2-3\\
f(6)=a(6-4)^2-3=2\]

Answer 5

\[4a-3=2\] solve for \(a\)

Answer 6

Solve for a? how i do that?

Answer 7

How to you get 4a-3=2?

Answer 8

@satellite73

Answer 9

Yeah I got it but how did you get 4a-3=2?