A height above ground, h metres, of a child on a swing, ranges from 0.5m to 1.5m The child reaches max height ever second. Initially there child is at minimum height. Express height as a function of time.
I get h(t)=0.5sin(1t)+1, is this correct?
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ganeshie8 (ganeshie8):
Very close! try this :
\[\large h(t)=0.5\sin(2\pi t)+1\]
ganeshie8 (ganeshie8):
that doesn't look correct either.. looks we need to slide the graph to right because the starting value is minimum
ganeshie8 (ganeshie8):
` Initially there child is at minimum height.`
ganeshie8 (ganeshie8):
try this instead :
\[\large y=0.5\sin\left(2\pi t-\frac{\pi}{2}\right)+1\]
OpenStudy (anonymous):
why 2pi t?
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ganeshie8 (ganeshie8):
because you want the period to be `1` :
`The child reaches max height ever second.`
ganeshie8 (ganeshie8):
the period of sin(t) is 2pi
since you want to reduce the period to 1, multiplying t by 2pi compresses the graph by a factor of 2pi