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Mathematics 22 Online
OpenStudy (anonymous):

A new car costs $120 000.After 1 year,its value decreases by 20%.For the second year,its value decreases a further 10%.What is the value of car after 2 years?

OpenStudy (anonymous):

@Mimi_x3 @RJaza @alekos @yamya70 @UsukiDoll @h

OpenStudy (anonymous):

@triciaal @Zale101 @perl @shrutipande9 @shamim @sweetburger

OpenStudy (anonymous):

@e.mccormick help me please

OpenStudy (anonymous):

@dan815 @dtan5457 @DiamondBear3299 @DeadShot

OpenStudy (e.mccormick):

Well, when it devalues by a percentage, you want to remove that percentage from the value. Do you know how to do that?

OpenStudy (e.mccormick):

There are two ways to figure a single devaluation. The first is to just take the full amount, or 100%, and subtract out the devalued amount. You find the devalued amount by multiplying be the percentage. \(100\% x - 20\% x\) Now, with a little algebra, I can convert that to the second method: I take \(100\% x - 20\% x\) and factor out the x to get: \((100\% - 20\%) x\) and that subtracts nicely to get: \(80\% x\) So, I can subtract the devalued percentage from 100% to get a multiplier percentage. That second way works just as well. Use either way and do it twice. Once for the first year to get the starting value for the second year. Then do it again for the second year. The result is the answrer.

OpenStudy (triciaal):

the above is correct

OpenStudy (anonymous):

here the amount is 120 000.and after 1 year 20% and after the 2nd year 10%. 20%-10%=10% now , 120 000 -1000=121000

OpenStudy (anonymous):

or 100%-30%=70%

OpenStudy (triciaal):

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