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What prime is greater than a perfect square and 7 less than the next-largest square?
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\(\Large \text{some where here} ~1,2,3,4,5,6,7\)
so i would say 3 since 1>3>4
wait ugh i thought less than 7 xD
sorry
Haha i thought the same, Marki
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lol its ok
haha 7 itself work
5 also
ok lets assume it 5 :3 4<5<9 and 7<9
Thanks for helping me I suck at problems with perfect squares involved
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me as well sometimes :P dont worry
So the answer is 7<9?
hmm the answer is 5
7 less than the next-largest square? means if we call the unknown prime "p", then p= (n+1)^2 - 7 where n^2 is the the square and (n+1)^2 is the next-largest square
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