Question

what are the asymptotic of y=(x+3) / (x^2-9) ?
The answer is x= 3, y= 0
Just need to show the work and don't know how to get there

Answer 1

HI!!

Answer 2

do you know how to factor \(x^2-9\)/

Answer 3

Yes, (x+3)(x-3)

Answer 4

K then cancel

Answer 5

what's left is (x-3)

Answer 6

you get
\[\frac{1}{x-3}\] which has a vertical asymptote when \(x=3\) because that makes the denominator equal to zero

Answer 7

Since the y has no number... I'm guess it's just 0?