Question

calculate the value o f(H30+) from the given (-0H) and label the solution as acidic or basic

a. 10^-8
(H30+)=_________*10^M

Answer 1

@dan815
You good in Chemistry?

Answer 2

"Assuming that the solution is aqueous, you look for the following: 1)pH <7, acidic; pH>7, basic, pH=7, neutral. If you are give pOH, then pOH>7 is acidic and pOH<7 is basic; you can calculate pH from pOH by subtracting pOH from 14. If you are given concentrations in 10^-x form, simply remember that pH (for H3O+ concentrations) and pOH (for OH- concentrations) are simply the 10 base logarithm of the negative of the concentration (Ex. pH of [H3O+] = 10^-4 = 4). Therefore, 1) is basic, 2) is neutral, 3) is basic, 4) is acidic, 5) is acidic (you can have a pOH of 14 - and a corresponding pH of ~0), and 6) is acidic."

Answer 3

@abb0t @dan815

Answer 4

You know pH = -log[H\(^+\)].
And
14 = pH + pOH


To solve for concentration, you eliminate the log, by raising both sides to the power of 10. This is basic algebra.

Answer 5

Base from what abbot said.

Known: [OH-] = 10^-8
Unknown: [H+] = ?

This is like the 3 steps we did before, but instead of finding [OH], we need to find [H+]

1. \(\sf pOH= -log [OH-]\) -> use this to find pOH

2. Using the calculated pOH, find pH by this formula: \(\sf pH=14 -pOH\)

3. After finding pH, apply this: \([H^+]= 10^{-pH}\)

same steps like we did before (:

Answer 6

is it -log( 10^-8)

Answer 7

to start the problem

Answer 8

yes, just continue doing it... i'll be checking it

Answer 9

p.s. don't delete your comments @toxicsugar22

Answer 10

14-8=6

Answer 11

is poH 8

Answer 12

yes...

Answer 13

PH IS 6

Answer 14

RIGHT

Answer 15

yep, then..?

Answer 16

{h+}=10^-6

Answer 17

right (:

now look at the \(\sf pH\), is it acidic or basic?

Answer 18

it is acidic

Answer 19

yes!

now , can you do the 2nd one now?

Answer 20

so how should i write the answer. should i say 1*10^-6

Answer 21

yes, it's the same

Answer 22

thanks

Answer 23

np

Answer 24

so the next one is 6.00*10^-9 M

h30+=_____*10^ M

Answer 25

I got the anwer i think, I want you to check it

Answer 26

is it -log(6.00*10^-9 )

Answer 27

then POH is 8.221

Answer 28

am i correct so far?

Answer 29

yes (:

Answer 30

then PH IS 5.779

Answer 31

mhmmm.. keep going

Answer 32

THEN IS THE ANWER H+=10^-5779

Answer 33

WHICH IS 5.779

Answer 34

AND IT IS ACIDIC

Answer 35

are you sure?

\(\sf [H^+]= 10^{-5.779}=? \) I got a different answer

Answer 36

try calculating it again (:

Answer 37

I GOT 5.779

Answer 38

for [H+] ?

if it's for pH, then it is 5.779

Answer 39

oh so ph is 5.779

Answer 40

yes, then do redo step 3

Answer 41

so then h+ = 8.221

Answer 42

right

Answer 43

and its basic

Answer 44

no no and no...

let's recap

step 1: you calculated pOH which is equal to 8.221

step 2: calculating pH which is 14-8.221 = 5.779

now do step 3: calculating \(\sf [H+]= 10^ {-5.779}\)

Answer 45

im getting 5.779

Answer 46

are you getting that

Answer 47

i put -log(10^-5.779) right

Answer 48

no, no need to get the -log 'coz you eliminated it

\(\sf pH= -log [H^+]\) evaluate this to solve for [H+] by raising both sides by base 10

therefore you'll have
\(\sf [H^+]= 10^{-pH}\)

Answer 49

if you calculated the log, you'll get the same result.

Answer 50

so it is 5.779

Answer 51

or no

Answer 52

or is it 1.6663

Answer 53

not quite right, it is \(\sf 1 \times 10^{-5.779}\) or \(\sf 1.663 \times 10^{-6}\)

calculate this

Answer 54

lol no need to calculate, i already did :3

just try doing it and see if you get the same

Answer 55

are you getting it?