use a half-angle formula to find the exact value of each expression sin 105
@aum
105 = 90 + 15 sin(105) = sin(90+15) = sin(90)cos(15) + cos(90)sin(15) = 1*cos(15) + 0*sin(15) = cos(15).
wait wouldnt it be 105*2
\[ \cos^2(\frac a2) = \frac 12\{1+\cos(a) \} \]
I am splitting 105 degrees into two parts: 90 degrees + 15 degrees. 90 degrees is a standard angle for which the sine and cosine are known values. So I use the sin(A+B) formula first: sin(A+B) = sin(A)cos(B) + cos(A)sin(B) with A = 90 and B = 15 degrees.
In my first reply I showed that sin(105) = cos(15). Now we use the half angle formula (in my second reply) and find cos(15). Set a = 30 in the half angle formula and find cos(15) and that will be the same as sin(105).
okay go on i get it
what should i do next
same thing we did for sin(15) in the previous problem. set a = 30 in the half angle formula above and find cos(15).
okay thank you
you are welcome.
one last one?
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