Graphing: Slope, Y-Int, Plotting.

Question

anonymous · Answer

attachment

legends · Answer

In think (1,1)

anonymous · Answer

Can you explain how you did it? I have 9 other questions like this lol.

legends · Answer

Since its (0,0) the slope is 1 so we move one unit to try to make a staight line.

anonymous · Answer

(6, -3) is the one I plotted. Would that be correct?

anonymous · Answer

Says it was incorrect.

legends · Answer

Alright so maybe witha slope of six, lets try what you said (6,3)

anonymous · Answer

I can't redo it lol. Here's my next problem.

legends · Answer

I don't know if the slope is 7 or you have to put it in a decimal

anonymous · Answer

We can plug it in point-slope form.

$y - y_1 = m(x - x_1)$

Where $y_1$ is the y-value of the point, $x_1$ is the x-value of the point, and $m$ is the slope.

So we have:

$y - 6 = \dfrac{7}{10}(x - 0)$

or

$y - 6 = \dfrac{7}{10}(x)$

Distribute 7/10 into the parenthesis:

$y - 6 = \dfrac{7}{10}x$

Add 6 to both sides:

$y = \dfrac{7}{10}x + 6$

Now we can plug in like '1' for 'x' and find another point..

$y = \dfrac{7}{10}(1) + 6$

$y = \dfrac{7}{10} + 6$

What's 6 + 7/10?

anonymous · Answer

We can just graph it to find another point: https://www.desmos.com/calculator/dcfdi0evcx

anonymous · Answer

I tried using that website but it wouldn't work for me
Guess I wasn't putting in the right formula

anonymous · Answer

Either way, thanks everybody for helping.