Question

limz->2 z^3-8/z-2

Answer 1

\[\lim_{z \to 2} \frac{z^3-8}{z-2}\]

Answer 2

Right??

Answer 3

yes @waterineyes

Answer 4

You must know that:
\[a^3-b^3 = (a-b)(a^2 + b^2 +ab)\]

Answer 5

Also, you can write \(8\) as \(2^3\)..

Answer 6

So:
\[z^3 - 8 = z^3 - 2^3\]

Answer 7

Applying that formula here, what will you get?