Question

q

Answer 1

I want to know the solutions of 3 questions mentioned in the trigonometry file. Anybody Help.

Answer 2

wish i could im bad at trig though

Answer 3

@robtobey

Answer 4

for third question, simply use the tangent ratio

Answer 5

Say elevations of \(A'\) and \(B'\) are \(h_1\) and \(h_2\) respectively :

\[\tan(A) = \dfrac{h_1}{a} \implies h_1 = a*\tan(A)\]

\[\tan(B) = \dfrac{h_2}{b} \implies h_2 = b*\tan(B)\]

Answer 6

question is asking for the difference : \(\large h_1 - h_2\)

Answer 7

h1 = ?

Answer 8

a * tan A = 100 * TAN 20 =H1

Answer 9

B* TANB = 200 * TAN 10 = H2

Answer 10

you have 3 columns,
maybe pick the values from first column for now :

```
A = 20
B = 10
a = 100
b = 200
```

\[\large h_1 = a*\tan(A) = 100*\tan(20) =36.397 \]
\[\large h_2 = b*\tan(B) = 200*\tan(10) = 35.265\]

\[h_1-h_2 = \cdots \]

Answer 11

ok.

Answer 12

what about other 2 questions , Are they right ?

Answer 13

*solutions

Answer 14

@ganeshie8

Answer 15

thanks for reply.

Answer 16

But I get different values for other 2 columns the value of h1-h2 differs !

Answer 17

@texaschic101

Answer 18

@iambatman

Answer 19

@eliassaab @Kainui @mathmate

Answer 20

yes it has to differ for other two columns because they have different distances and angles

Answer 21

other ! 2 solutions are they correct ?

Answer 22

ok . Can you check the first 2 solutions plz.

Answer 23

@ganeshie8

Answer 24

first one looks right,
second one doesn't

Answer 25

can you tell me the mistake .

Answer 26

\[\large \sqrt{a^2} \ne a\]

\[\large \sqrt{a^2} = |a|\]

Answer 27

ok , what is the mistake then ?

Answer 28

look at `sin(x/2)` graph between x=2pi and 4pi :

http://gyazo.com/4f6daf522c3e9b5e724a28945925afda

Answer 29

Notice that it is negative, so :

\[\sqrt{\sin^2\left(\frac{x}{2}\right)} = \left|\sin\left(\frac{x}{2}\right)\right| = -\sin\left(\frac{x}{2}\right)\]

Answer 30

so , what are the values of theta ?

Answer 31

we're done, the questions is only about simplifying the given expression. there is nothing to solve here

Answer 32

for the indicated values of the angle. it says !

Answer 33

Right, when \(2\pi \lt\theta \lt 4\pi\) we have
\[\sqrt{\sin^2\left(\frac{\theta}{2}\right)} = \left|\sin\left(\frac{\theta}{2}\right)\right| = -\sin\left(\frac{\theta}{2}\right)\]

thats the end of story

Answer 34

that's it then, Thank you very much .

Answer 35

np:)