Question

If (x + 2) is a factor of x^3 − 6x^2 + kx + 10, k=? Medal and fan!!

Answer 1

so if (x + 2) is a factor then x = -2 is a zero

so substitute x = -2 into the equation...

and find the value of k, that makes it zero..

hope it helps

Answer 2

\(\large \begin{align} \color{black}{
\normalsize \text{ (x + 2) is a factor of f(x)= x^3 − 6x^2 + kx + 10} \hspace{.33em}\\~\\
\normalsize \text{ -2 must be the root of the function .}f(x) \hspace{.33em}\\~\\
f(-2)= 0 \hspace{.33em}\\~\\
f(-2)= (-2)^3 − 6(-2)^2 + k(-2) + 10 \hspace{.33em}\\~\\
\normalsize \text{so} \hspace{.33em}\\~\\
(-2)^3 − 6(-2)^2 + k(-2) + 10=0 \hspace{.33em}\\~\\
}\end{align}\)

Answer 3

(-2)^3=-8

Answer 4

\[ (-2)^3 -6 \times (-2)^2 + k \times (-2) + 10 = 0\]

simplify it and then solve for k

and (-2)^3 = -8