Question

The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:



y = (1/20)x²

y = -(1/20)x²

x = (1/20)y²

Answer 1

@Directrix help please

Answer 2

I can check options.

Answer 3

Look here for option A and scroll down to the properties table:

http://www.wolframalpha.com/input/?i=Focus+y+%3D+%281%2F20%29x%C2%B2

Answer 4

Same instructions for option B

http://www.wolframalpha.com/input/?i=Focus+y+%3D+-%281%2F20%29x%C2%B2

Answer 5

Same instructions for option C

http://www.wolframalpha.com/input/?i=Focus+x+%3D+%281%2F20%29y%C2%B2

Answer 6

so its A

Answer 7

@Directrix ?

Answer 8

Correct, A

Answer 9

i have a few more

Answer 10

Given the equation of the parabola -36y=x^2
The focus of the parabola is:


(0, 9)

(-9, 0)

(0, -9)