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OpenStudy (anonymous):
i need help
OpenStudy (sleepyjess):
With?
OpenStudy (anonymous):
Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting two slanting rods, one of which, labeled PR, is shown:
A support structure is shown in which a right triangle PQR is formed with the right angle at Q. The length of PQ is shown as 14 feet, and the length of QR is shown as 6 feet..
Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer, stating the theorem you used. Show all your work. (5 points)
Part B: The length of rod PR is adjusted to 16 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work. (5 points)
OpenStudy (sleepyjess):
Is there a picture?
OpenStudy (anonymous):
ya but how do i put pics on here
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OpenStudy (sleepyjess):
Save it to your computer, then click Attach File
OpenStudy (anonymous):
You can take a printscreen, use 'Snipping Tool', or save it.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
here
OpenStudy (sleepyjess):
Ok, do you know Pythagorean's Theorem?
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OpenStudy (anonymous):
i need to be explained to me i have the aweser
OpenStudy (anonymous):
plz
OpenStudy (sleepyjess):
Do you know Pythagorean's Theorem?
OpenStudy (anonymous):
no i forgot it
OpenStudy (sleepyjess):
\(a^2+b^2=c^2\)
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OpenStudy (anonymous):
ok
OpenStudy (sleepyjess):
Just substitute in the numbers given.
OpenStudy (anonymous):
ok....
OpenStudy (anonymous):
\[14^2-6^2=8^2\]
OpenStudy (anonymous):
ok....
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OpenStudy (sleepyjess):
huh?
OpenStudy (sleepyjess):
No
OpenStudy (anonymous):
what do you mean
OpenStudy (sleepyjess):
You are given 14 and 6, where is 8 from?
OpenStudy (sleepyjess):
and it is adding.
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OpenStudy (anonymous):
that is after i - 14-6
OpenStudy (anonymous):
14-6=8
OpenStudy (sleepyjess):
That isn't how it's done.... you have to solve for \(c^2\)
OpenStudy (sleepyjess):
\(14^2 + 6^2 = c^2\), solve for \(c^2\)
OpenStudy (anonymous):
how
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OpenStudy (sleepyjess):
what is \(14^2\)?
OpenStudy (anonymous):
196
OpenStudy (sleepyjess):
what is 6^2?
OpenStudy (anonymous):
36
OpenStudy (sleepyjess):
now add those
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OpenStudy (anonymous):
232
OpenStudy (sleepyjess):
Ok, \(232=c^2\), square root of both sides give \(x=c\)
OpenStudy (anonymous):
what
OpenStudy (sleepyjess):
what is the square root of 2323
OpenStudy (sleepyjess):
*232
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OpenStudy (anonymous):
15.2
OpenStudy (sleepyjess):
yep, so that is all for part a
OpenStudy (sleepyjess):
Ok, now we need to solve for \(a^2 + 14^2 = 16^2\).
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@sleepyjess
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OpenStudy (sleepyjess):
We know that 14^2 is 196, so what is 16^2?
OpenStudy (anonymous):
ok it is 256
OpenStudy (anonymous):
196 is 14^2
OpenStudy (sleepyjess):
Ok, so now we have \(a^2+196 = 256\). Subtract 196 from both sides.
OpenStudy (anonymous):
196-196=0
256-196=60
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OpenStudy (sleepyjess):
Yep, so \(a^2=60\), square root of 60?
OpenStudy (anonymous):
7.7
OpenStudy (sleepyjess):
Yes, so a = 7.7
OpenStudy (anonymous):
so thats it
OpenStudy (sleepyjess):
Yes
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OpenStudy (anonymous):
ok thank you
OpenStudy (sleepyjess):
\(\LARGE\cal\color{#ff0074}{No~Problem!}\\\bbox [10pt, #00ffab,border:5pt solid blue ]{\color{#872AF0}{\huge\cal ~\dagger~\heartsuit sleepyjess~\heartsuit~\dagger}}\)