Math help please and thank you :)

Variable y varies directly with x^2, and y = 96 when x = 4.

What is the value of y when x = 2?
y=

Question

Math help please and thank you :)

Variable y varies directly with x^2, and y = 96 when x = 4.
 
What is the value of y when x = 2?
y=

anonymous · Answer

hello?

displayerror · Answer

Variable $y$ varies directly with $x^2$, meaning that as the values of$x$ increases, the value of $y$ also increases.

Consider the example that they've provided you with. The function is given by $y = Ax^2$, where $A$ is some constant (it doesn't change). What is the value of $A$? That's what we have to find out first, and that is why we are given the example.

$$96 = A (4)^2$$
Solve for $A$ here. Then plug in the new information and solve for $y$, only this time our $x$ value is 2 (we're solving the question that is being asked)
$$y = A(2)^2$$

arabpride · Answer

Don't forget to close this post if you're done.
Thanks! :3