how would I write an equation of a line passing through the points (-2, -1) and (0, 4). Write the final answer in slope-intercept form.
Well first find the slope, using the following formula: \[m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\] where your coordinates represent \[(x_1,y_1)~~\text{and}~~(x_2,y_2)\] Once you manage to get that, plug in m and your first coordinates in the point - slope form: \[y-y _{1}=m(x-x _{1})\] do some little algebra and eventually you will have slope - intercept form \[y=mx+b\]
K thank you very much!
Y=2 1/2+2 does that answer look right?
Mhm, not quite
What is your slope?
is it Y=2 1/2+5
No, what happened to your x?
Use iambatmans steps
haha I did
Well lets do it together, step by step :), can you show me what you got for the slope?
2 1/2
Right, but lets stick to 5/2
ok so now lets use point slope form, can you show me how you would do it
y-y1=m(x-x1)
Yeah, so plug in y1, x1 and m into the equation, leave y and x alone
\[y+1=5/2 (x+2)\] right? And we want y = mx+b
y-(-1)=2 ½(x+2)
Yeah, that's fine, now we just do some algebra :)
so distribute 5/2 over (x+2) and then move +1 to the right! And we're done
Y=5/2x+6
Subtract -1 not add :P
But good job!
K thanks a lot for the help!
HI!!
No problem :)
did you get the slope?
you already have the y intercept
the points (-2, -1) and (0, 4)... since the point \((0,4)\) is on the graph, the y intercept is \(4\)
Yes, that's right, we could always use that to check our answer! :)
?
no checking involved find \(m\) and write \[y=mx+4\]
Yes, I know but it's good to use other methods and seeing what's going on as well.
haha sorry but you guys' are confusing me:]
Don't worry about it haha, you can use any method, I usually prefer using what misty said after you understand the above method :P
As you get used to point slope form and slope intercept and see a relationship between them, it's pretty neat actually.
K thanks!
Np, thank you Misty :)
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