Question

Please help, will medal

2a-9 4a+4
—— • ——
2a-6 a+3

Answer 1

HI!!

Answer 2

see if you can factor and cancel some stuff

Answer 3

for example, \(4a+4=4(a+1)\)

Answer 4

oh ok just a sec

Answer 5

how about \(2a-6\) can you factor that one?

Answer 6

ya ok so it would be 2a-6 = 2(a-3) ?

Answer 7

yes

Answer 8

but not much cancels here anways, just a little

Answer 9

so we've got

2a-9 4(a+1)
—— • ——-
2(a-3) a+3

Answer 10

you get
\[\frac{2a-9)4(x+1)}{2(x-3)(x+3)}\]

Answer 11

ooh i got the questions marks of death, let me refresh and see if they go away

Answer 12

whoa ya that

Answer 13

kk so all that cancels is a lousy 2 `

Answer 14

\[\frac{(2a-9)4(x+1)}{2(x-3)(x+3)}=\frac{(2a-9)2(x+1)}{(x-3)(x+3)}\]

Answer 15

i guess if you have to you must multiply this mess out

Answer 16

I believe that is what they want...

Answer 17

then if you have to , you have to
the denominator is easy right?

Answer 18

if not let me know and i can show you what it is

Answer 19

I'm sorry, I do really poorly at this :( please explain...

Answer 20

ok lets do the bottom first

Answer 21

\[(a+3)(a-3)=a^2+3a-3a+9=a^2-9\]

Answer 22

or you can remember that \((a+b)(a-b)=a^2-b^2\) always but you can also just multiply

Answer 23

Oh! yes ok I remember now!

Answer 24

the top is
\[2(2a-9)(a+1)\] so lets multiply \[(a-9)(a+1)\] then by 2

Answer 25

oops typo

Answer 26

lets multiply
\[(2a-9)(a+1)\] doing four multiplications, sometimes they say "foil"

Answer 27

you want to try it first?

Answer 28

yes I remember foil

Answer 29

just a minute I'm doing it on paper, then I'll have you check it to see if its right, ok?

Answer 30

kk

Answer 31

wouldn't it be (2a-9) (2(a+1)) because of the 2 originally in front of a+1?

Answer 32

yeah it would, but it would be easier to do
\[(2a-9)(a+1)\] first and then double everything

Answer 33

Oh does it come out the same?

Answer 34

or you could just do
\[(2a-9)(2a+2)\] if you prefer

Answer 35

yes, multiplication is "associative" it doesn't matter which one you do first

Answer 36

oh ok

Answer 37

4a2 - 14a - 18 ?

Answer 38

4a^2 *

Answer 39

yes!!

Answer 40

final answer \[\frac{4a^2-14a-18}{a^2-9}\]

Answer 41

yay! thank you so much!

Answer 42

\[\color\magenta\heartsuit\]