OpenStudy (anonymous):

can someone show me how to do THE PYTHAGOREAN THEOREM

OpenStudy (anonymous):

\(a^2 + b^2 = c^2\) Where 'a' and 'b' are the two legs of the right triangle, and 'c' is the hypotenuse. This is used to find the other sides of a right triangle only.

OpenStudy (anonymous):

@KenichiIvy I believe you have the formula wrong.

OpenStudy (sleepyjess):

Lets say we have a right triangle with the legs 6 in and 9 in. Now we need to find the hypotenuse. We substitute those numbers into the Pythagorean Theorem, \(a^2+b^2=c^2\) to find the hypotenuse. a and b are the legs, c is the hypotenuse. \(6^2+9^2=c^2\)

OpenStudy (anonymous):

Thanks for the correction @iGreen.

OpenStudy (anonymous):

dido

OpenStudy (sleepyjess):

Now, we square 6 and 9, giving us \(36+81=c^2\). Add 36 and 81, gives us 117. So now we get \(117=c^2\). Now take the square root of both sides, and that is it.

OpenStudy (anonymous):

and how is it completed i see square roots

OpenStudy (anonymous):

|dw:1424266428820:dw|

OpenStudy (sleepyjess):

We get \(\sqrt{117} = c\), so that is the hypotenuse. If you want to put \(\sqrt{117}\) into a calculator to get the exact value, then you can.

OpenStudy (anonymous):

????

OpenStudy (sleepyjess):

Ok, so we need to solve that one?

OpenStudy (anonymous):

yes

OpenStudy (sleepyjess):

Ok, can you do the first step of substituting in the known values?

OpenStudy (anonymous):

?????????????? x(

OpenStudy (sleepyjess):

We have 2 known values, 4 and 7. Those can be substituted for a and b into the Pythagorean Theorem.

OpenStudy (anonymous):

oh 4sq*7sq=Csq correct?

OpenStudy (sleepyjess):

Yes! Now what is \(4^2\)?

OpenStudy (anonymous):

i mean +

OpenStudy (sleepyjess):

oh yes, I didn't catch that haha I will be right back :)

OpenStudy (anonymous):

k

OpenStudy (sleepyjess):

ok, I'm back so what is \(4^2\)?

OpenStudy (anonymous):

4*4 witch is 16 correct?

OpenStudy (sleepyjess):

Yep, now \(7^2\)?

OpenStudy (anonymous):

7*7=42?

OpenStudy (sleepyjess):

Close, 42 is 7*7. 7*7 = 49

OpenStudy (sleepyjess):

\(\color{blue}{\text{Originally Posted by}}\) @sleepyjess Close, 42 is 7*7. 7*7 = 49 \(\color{blue}{\text{End of Quote}}\) Correction, 42 is 7*6

OpenStudy (anonymous):

k

OpenStudy (sleepyjess):

So now we get \(16+49=c^2\) What is 16+49?

OpenStudy (anonymous):

65

OpenStudy (sleepyjess):

Yep, now the square root of 65

OpenStudy (sleepyjess):

and \(\sqrt{c^2}\) which is just c

OpenStudy (anonymous):

65*65=4225

OpenStudy (sleepyjess):

The square root, not squared. Squared is \(65^2\), square root is \(\sqrt{65}\)

OpenStudy (anonymous):

k so 8.062

OpenStudy (sleepyjess):

Yep :)

OpenStudy (anonymous):

k thanx

OpenStudy (sleepyjess):

Lastly, welcome to OpenStudy! If you have any questions about the site, feel free to ask me ^_^

OpenStudy (anonymous):

k will do