can someone show me how to do THE PYTHAGOREAN THEOREM
\(a^2 + b^2 = c^2\) Where 'a' and 'b' are the two legs of the right triangle, and 'c' is the hypotenuse. This is used to find the other sides of a right triangle only.
@KenichiIvy I believe you have the formula wrong.
Lets say we have a right triangle with the legs 6 in and 9 in. Now we need to find the hypotenuse. We substitute those numbers into the Pythagorean Theorem, \(a^2+b^2=c^2\) to find the hypotenuse. a and b are the legs, c is the hypotenuse. \(6^2+9^2=c^2\)
Thanks for the correction @iGreen.
dido
Now, we square 6 and 9, giving us \(36+81=c^2\). Add 36 and 81, gives us 117. So now we get \(117=c^2\). Now take the square root of both sides, and that is it.
and how is it completed i see square roots
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We get \(\sqrt{117} = c\), so that is the hypotenuse. If you want to put \(\sqrt{117}\) into a calculator to get the exact value, then you can.
????
Ok, so we need to solve that one?
yes
Ok, can you do the first step of substituting in the known values?
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We have 2 known values, 4 and 7. Those can be substituted for a and b into the Pythagorean Theorem.
oh 4sq*7sq=Csq correct?
Yes! Now what is \(4^2\)?
i mean +
oh yes, I didn't catch that haha I will be right back :)
k
ok, I'm back so what is \(4^2\)?
4*4 witch is 16 correct?
Yep, now \(7^2\)?
7*7=42?
Close, 42 is 7*7. 7*7 = 49
\(\color{blue}{\text{Originally Posted by}}\) @sleepyjess Close, 42 is 7*7. 7*7 = 49 \(\color{blue}{\text{End of Quote}}\) Correction, 42 is 7*6
k
So now we get \(16+49=c^2\) What is 16+49?
65
Yep, now the square root of 65
and \(\sqrt{c^2}\) which is just c
65*65=4225
The square root, not squared. Squared is \(65^2\), square root is \(\sqrt{65}\)
k so 8.062
Yep :)
k thanx
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k will do
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