Helpful steps,How much heat , in kJ, is required to warm 1.50L of water from 25.0oC to 100.0oC? (Assume a density of 1.0g/mL and a specific heat of 4.184J/(g*oC) for the water.) Use proper significant figures. ( When I calculated this and got 470.7 and rounded to my answer 471 is this correct?)

Question

dtan5457 · Answer

If the density is 1.0g/ml.  Normally, you would get the mass of the water first as the formula for heat is 
$$q=cp \times m \times \Delta Tc$$
cp (specific heat) is given at 4.184j
tc (temperature change) is 75
and m=mass.

given the density is 1 and volume is 1.5 liters.

density=mass/volume

only problem i see here is the units...the volume should be in milliliters..to it corresponds with the density unit...

1.0 g/ml=1500ml times mass

mass=1500 grams

now plug that into the formula again

mass=1500 grams

anonymous · Answer

That's exactly what I did and I got 471 kj as my answer