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Mathematics 7 Online
OpenStudy (nerdgirl):

PLEASE HELP!! Will medal and fan!! At greater depths, a diver uses the air in the tank more quickly. Assume that the amount of time the air will last is inversely proportional to the pressure at the depth of the dive. Suppose a tank has enough air to last 60 min at the surface. How long will it last at a depth of 99 ft? (The pressure is 4 atm, or 4 times as great.)

OpenStudy (nerdgirl):

@kirbykirby @torifamelol @The.Cool.Man @XainSG

OpenStudy (anonymous):

Sorry but it won't last very long that is all I can say. I can't help you though so sorry 3':

OpenStudy (nerdgirl):

@BryceHale @k_lynn @Riamarializz @ribhu

OpenStudy (kirbykirby):

If \(T\) is the time in minutes, and \(P\) is the pressure in atm, then if time is inversely proportional to pressure, this means you have the expression \[T=\frac{k}{P} \] where k is just a proportionality constant

OpenStudy (kirbykirby):

Now we don't have \(k\), so we can find it. They say the tank lasts 60 min at the surface. Usually, the surface pressure is about 1 atm. This is probably safe to assume since they don't give extra info. So, from this, you can immediately find \(k\). Then, since we know \(k\), you can find the amount of time left in the tank when \(P=4 ~\text{atm}\)

OpenStudy (nerdgirl):

Sorry but I've been at this for hours so my brain is kind of totaled. What would k be?

OpenStudy (kirbykirby):

Well you have T = 60, and you have P = 1 so.. \[T=\frac{k}{P}\\ \\ ~\\ 60 = \frac{k}{1} \]

OpenStudy (nerdgirl):

Ohhhh I see. I think I'll be able to take it from here... thanks so much! :)

OpenStudy (kirbykirby):

:) np

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