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Algebra 15 Online
OpenStudy (anonymous):

Match the function with its correct description.

OpenStudy (anonymous):

OpenStudy (anonymous):

A. The degree of the function is 4, and the leading coefficient is positive.

OpenStudy (anonymous):

B. The degree of the function is 5, and the leading coefficient is negative.

OpenStudy (anonymous):

C. The degree of the function is 6, and the leading coefficient is negative.

OpenStudy (anonymous):

D. The degree of the function is 5, and the leading coefficient is positive.

OpenStudy (solomonzelman):

When you have \(\large\color{slate}{ f(x)=(-x+1)^3(x+2)^2(x-3) }\). \(\large\color{slate}{ f(x)=(-x+1)^3 }\) yields a degree of 3, when you multiply it times \(\large\color{slate}{ (x+2)^2 }\) you have (the biggest) power of \(\large\color{slate}{ 5 }\) then when you multiply all "that" (which will have the degree of 5) times \(\large\color{slate}{ (x-3) }\) then your degree will go up by 1.

OpenStudy (solomonzelman):

so your biggest power would be?

OpenStudy (anonymous):

6?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

@ribhu

OpenStudy (solomonzelman):

yes, 6 is the degree

OpenStudy (solomonzelman):

so your answer is?

OpenStudy (anonymous):

The degree of the function is 6, and the leading coefficient is negative.

OpenStudy (solomonzelman):

yes.

OpenStudy (solomonzelman):

also, the leading coefficient is negative, because you are multiplying all positive X's besides -x in the first term which with it's odd power (of 3) will still be negative

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