Question

Here! :)

Answer 1

@pitamar

Answer 2

Didn't we just solve this one?

Answer 3

yes and sorry about that

Answer 4

Ok. So we know that the train travels at the same constant speed all the time.
We know that last month she rode 90 miles and this month 60. We're told last month she rode 1 hour more than this month.
What this means is that within that extra hour she rode last month she covered another 30 miles compared to this month.
so 1 hour = 30 miles.
60 miles = 2 hours.

Answer 5

ok i gotcha so far

Answer 6

do you have to fill the table on the right too?
because we have the hours she traveled this month.

Answer 7

no just the hours on the left

Answer 8

k so done. 2 hours

Answer 9

ok 2 gotcha cool

Answer 10

only one more

Answer 11

Ok, but you should try on your own first. If you get in troubles then ask for help

Answer 12

ok so for tis one I got 1 but im not sure how that converts to a answer

Answer 13

Well, to be honest this isn't an easy question lol

So we're told we have a fast boy that can wash the dogs in 3 hours only and a slow boy that could do that in 4 hours.
What I suggest is to forget about the dogs. Let's talk about 'the job'. The fast boy can complete 'the job' alone in 3 hours, while the slow boy can do it in 4 hours.

If they work together then each one of them completes a part of 'the job'.
They'd still complete the job, so the parts that each one of them completed would sum up to cover the entire job needed to be done.
For example, if you and I had to wash 8 dogs, and we worked together for 2 hours and finished the job, then at the end maybe I washed only 3 dogs and you did 5, but together we washed all the 8 dogs.

If I'd give the two boys exactly the same amount of time to work, the amount of work each one of them covered would be different of course. the faster boy will do more within that amount of time.
We could say that in 3 hours the fast boy would have finished the entire job, but in 3 hours the slow boy would have only finished 3/4 of the job, he needs another hour to finish it.

So say they work together side by side. I want to know what amount of work did the fast boy do in order to complete the job. The rest of the work was covered by his slower friend.
So let \(x\) be the work (out of the entire job) that the fast boy did and we know that whatever work the fast boy did, the slower boy covered only 3/4 of it. so the slower boy did \(\frac{3}{4}x\) of the entire job.
Together those amounts of work sum up to the entire job (1):
$$
x + \frac{3}{4}x = 1
$$Now we just have to solve for x:
$$
\frac{4}{4}x + \frac{3}{4}x = 1 \\
\frac{7}{4}x = 1 \\
x = \frac{4}{7}
$$So at the end of the common work, the fast boy ended up doing \(\frac{4}{7}\) of it.
We know the fast boy would have need 3 hours to complete the entire job, so if it completed only \( \frac{4}{7} \) of the job, it means he worked only for:
$$
3 \cdot \frac{4}{7} = \frac{12}{7} = \frac{7 + 5}{7} = 1 \frac{5}{7}
$$So they worked for \( 1 \frac{5}{7} \) hours.

Answer 14

dang dude