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Chemistry 23 Online
OpenStudy (pounce0129):

How would you find the pH of a solution with a [H+] of 4.56 x 10^-5

OpenStudy (justin_lee):

pH is found by taking the log10 of the inverse amount of hydrogen ions: \[pH = \log_{10} (\frac{ 1 }{ [H ^{+}] }) = -\log_{10}([H ^{+}]) \] Just plug in the concentration of hydrogen into the -log operator. Let me know what you get for pH so that I can confirm.

OpenStudy (pounce0129):

@Justin_Lee i got 4.34

OpenStudy (justin_lee):

I got that too.

OpenStudy (pounce0129):

you are a life saver, thank you soooo much :)

OpenStudy (pounce0129):

@Justin_Lee can you help me with one more?

OpenStudy (justin_lee):

Sure.

OpenStudy (pounce0129):

find the pH of a 2.3 L solution containing 4.5 grams of HNO3

OpenStudy (justin_lee):

Your first step is to convert the grams value to concentration. Do you know how to do that?

OpenStudy (pounce0129):

so like grams per liter?

OpenStudy (justin_lee):

What were the units of the 4.56 x 10^-5 that you posted before? grams/L or M?

OpenStudy (pounce0129):

it just says [H+]

OpenStudy (justin_lee):

Hydrogen and hydronium ions are usually represented as concentrations of M (mols/L). Do you know how to convert from grams to mols?

OpenStudy (pounce0129):

yes, so i would be 4.5/63.012

OpenStudy (pounce0129):

*it

OpenStudy (pounce0129):

and you would get 0.0714 moles

OpenStudy (justin_lee):

Yup. Now convert from mols to concentration.

OpenStudy (pounce0129):

@Justin_Lee i got 1.51, is that right?

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