How would you find the pH of a solution with a [H+] of 4.56 x 10^-5
pH is found by taking the log10 of the inverse amount of hydrogen ions: \[pH = \log_{10} (\frac{ 1 }{ [H ^{+}] }) = -\log_{10}([H ^{+}]) \] Just plug in the concentration of hydrogen into the -log operator. Let me know what you get for pH so that I can confirm.
@Justin_Lee i got 4.34
I got that too.
you are a life saver, thank you soooo much :)
@Justin_Lee can you help me with one more?
Sure.
find the pH of a 2.3 L solution containing 4.5 grams of HNO3
Your first step is to convert the grams value to concentration. Do you know how to do that?
so like grams per liter?
What were the units of the 4.56 x 10^-5 that you posted before? grams/L or M?
it just says [H+]
Hydrogen and hydronium ions are usually represented as concentrations of M (mols/L). Do you know how to convert from grams to mols?
yes, so i would be 4.5/63.012
*it
and you would get 0.0714 moles
Yup. Now convert from mols to concentration.
@Justin_Lee i got 1.51, is that right?
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