Question

How much force, in Newtons, is applied to a 4 kg bowling ball that goes from 0 m/s to 5m/s in .5 seconds

Answer 1

hints:

F=ma, where F=force in newtons, m=mass in kg,
acceleration=\((v_f-v_i)/\Delta t\) = (5-0)/0.5 m/s^2

Answer 2

would it be 20 newtons?

Answer 3

Remember to divide the change in velocity by the time lapse:
F=ma = 4 ( (5-0)/0.5 ) = ?