Hi, I've got the Barron's ACT Flashcard Set and one of the questions seems a little off: Multiple-Choice 76 If (3x + a) · (x + b) = 3x^2 - 19x - 14, what are a and b? A. a=1, b=19 B. 1=2, b=7 C. a=-1, b=14 D. a=2, b=-7 E. a=1, b=-14 I did the FOIL, but it doesn't get rid of x all the way, so I can't figure out how to get a and b. Thank you!
first expand (3x + a)(x + b) = 3x^2 + 3bx + ax + ab = 3x^2 + x(3b + a) + ab
now compare coefficients with 3x^2 - 19x - 14 = 0
this gives 3b + a = -19 ab = -14 solve this system of equations
* ignore the '= 0' call it a typo!
What does it mean to compare coefficients? Wouldn't that be to set them equal to each other?
yes the coefficient of x in one expression is 3a+b and the other its -19 so we can set them equal
i should have said equate coefficents
So wouldn't that give us 3x^2 + x(3b + a) + ab = 3x^2 - 19x - 14 ?
right - though there should be an identity sign not an equal sign in between
|dw:1425228790002:dw|
an identity differs from an equation in that an identity is true for all values of the variable as its an identity we can equate coefficients
Strictly speaking the original equation should have used the identity sign not the '='.
Join our real-time social learning platform and learn together with your friends!