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Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.
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@satellite73
First find the vertex.
vertex is (0, 0)?
Yes
Now find the difference between the vertex and the vertex. We call this \(p\).
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whoops
Difference between focus and vertex
9?
Well, it's \(-9\).
Anyway, equation will be given by: \[ (x-x_0)^2=4p(y-y_0) \]Where \((x_0,y_0)\) is the vertex, and \(p\) is what we already discuss.
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x^2 = -36y
Yes
That was a lot easier than I thought...
Thanks :)
no problem
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