Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (sleepyjess):

Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.

OpenStudy (sleepyjess):

@satellite73

OpenStudy (anonymous):

First find the vertex.

OpenStudy (sleepyjess):

vertex is (0, 0)?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Now find the difference between the vertex and the vertex. We call this \(p\).

OpenStudy (anonymous):

whoops

OpenStudy (anonymous):

Difference between focus and vertex

OpenStudy (sleepyjess):

9?

OpenStudy (anonymous):

Well, it's \(-9\).

OpenStudy (anonymous):

Anyway, equation will be given by: \[ (x-x_0)^2=4p(y-y_0) \]Where \((x_0,y_0)\) is the vertex, and \(p\) is what we already discuss.

OpenStudy (sleepyjess):

x^2 = -36y

OpenStudy (anonymous):

Yes

OpenStudy (sleepyjess):

That was a lot easier than I thought...

OpenStudy (sleepyjess):

Thanks :)

OpenStudy (anonymous):

no problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!