Solve the initial value problem analytically:
dy/dx = 1 + x + (x^2/2) y(0)=1

Question

Solve the initial value problem analytically:
dy/dx = 1 + x + (x^2/2)     y(0)=1

perl · Answer

did you try integrating

anonymous · Answer

I know you need to integrate but I think that's where I'm having problems. The answer in the back of the book is not at all like my answer.

perl · Answer

$$\large \frac{dy}{dx} = 1 + x + \frac{x^2}{2} ~~,~~y(0)=1\
\large y(x) = x + \frac{x^2}{2} + \frac{1}{2}\cdot \frac{x^3}{3} + C \
\large y(0) = 0 + \frac{0^2}{2} + \frac{1}{2}\cdot \frac{0^3}{3} + C \
\large y(0) = 1 \
\large \iff \
 C = 1 

$$

anonymous · Answer

Oh so dx just means I need to find the antiderivative of that. Got it that's what was confusing me I guess. Okay thank you again Perl. I've got a test tomorrow and you may have saved my life

perl · Answer

your welcome