I have to prove that sqrt 11 is irrational, which I have done, ..Is sqrt11 + 3 irrational, please prove?????? Does my head in I tell you :)
\[\sqrt{11}+3\]?
prove it is irrational by using proof by contradiction
I am a bit lost with the plus 3 new to this
suppose \(\sqrt{11}+3\) is rational
then \[\sqrt{11}+3=\frac{a}{b}\] a,b integers
then \[\sqrt{11}=\frac{a}{b}-3\]
still with you :)
\[\frac{a}{b}-3\] is a rational number but \[\sqrt{11}\] is not this is a contradiction thus \(\sqrt{11}+3\) is irrational
Is that all I need to say?
what else would you need to add?
ahhhhh because regardless you are still dealing with an irrational number and nothing will change that?
unless you had alot of time on your hands LOL
Is this a correct assumption?
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