Question

how would i write y-3=4(x+1) in standard form

Answer 1

writing equation in standard form?

y+2= -3/4 (x+1)

Standard form consists of these 7 parts in this order:

1. A positive whole number (if possible)
2. The letter x multiplied by the number in 1
3. A plus or minus sign
4. A whole number (if possible)
5. The letter y multiplied by the number in 4
6. An equal sign
7. A whole number (if possible)

y + 2 = -3/4(x + 1)

Multiply both sides by 4 to clear of fractions:

4(y + 2) = 4[-3/4(x + 1]]

Distibute the 4 on the left. Cancel the 4's on the right:

1
4y + 8 = 4[-3/4(x + 1]]
1

4y + 8 = -3(x + 1)

Distribute the 3 on the right

4y + 8 = -3x - 3

Add 3x to both sides:

4y + 8 + 3x = -3x - 3 + 3x

4y + 8 + 3x = -3

Subtract 8 from both sides

4y + 8 + 3x - 8 = -3 - 8

4y + 3x = -11

Reverse the terms on the left:

3x + 4y = -11

Answer 2

@sarimari thank you

Answer 3

your welcome any other question ?

Answer 4

not right now

Answer 5

okay