A wooden box of bolts has a mass of 250kg and requires a horizontal force of 2100N to slide it along a horizontal wooden surface at a constant speed. It has a coefficient of friction of 0.86.
If the box were to be kept moving constantly at twice this speed what force would be needed to maintain this constant velocity
First, find the normal contact force or N - it is the force that acts opposite to the force applied to the floor and in this case it is its weight. N=weight=mg=250*10=2500N Secondly, for a body to move at constant speed, it means that both driving (Fd) and Resistive (R) forces are equal, meaning R=Fd The R=$N, where $ is the coeffient of friction and your Fd is 2100N
So, FR = 2150?
Frictional force=coefficient of friction*weight=0.86*250*9.8=?
2107N
So, if we keeping increasing the speed, the force never changes?
2107 is greater than 2100N
Ahsome, is your g 10 or 9.8?
9.8
Wait, your answer is 2107
2107-2100=7N makes the body acceleration.not keep constant velocity
Ok. So if we keep increasing the speed, the force doesn't change?
Unless we can consider as rounded to 2100N, because the question announces that that force causes a constant speed, dont you think @shamim?
I would say so. Its probably because i use 9.8
Ya. Frictional force will b equak to 2100N
So g will b less than 9.8. Right?
Isn't it a bit more? 9.81 something
g=9.81 makes frictional force more than 2107N
Guys, I think they have rounded.
Ya rounded
So, having that considered, I say we foollow the momentum's formula: Ft/m=v, meaning if F doubles, v doubles, hence to maintain double the constant speed, the force has to be 2100*2=4200N.
No @Holos
Constant velocity but the value is doubled . Needs 2100N applied force
Frictional force=2100N Applied force=2100N Both r ewual n oposit So cancelled each other
Exactly, @shamim. The velocity is doubled, but the force needed to sustain stays the same, since friction doesn't increase as you increase your speed.
Thanks @shamim and @Hoslos. You guys were really helpful :)
U r most welcome
:). Would you guys be able to help me with another question?
Of course. But u should ask question in main page
Yah
Yes, whenever I can possibly explain. I am here.
I'l make a new question. See you guys there :)
Anyway the formula will b F*t=mv-mu F*t/m=v-u @Hoslos
And this formula is for changing velocity. Right? @Hoslos
Yes, but since the v is constant, guess we can use v as the same.
When v is constant u will write v-u=0
Exactly.
Let us go help Ahsome, shall we? Let us keep warming up!
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