Solve the equation: x^3-13x^2+47x-35=0 given that 1 is zero of f(x)=x^3-13x^2+47x-35

Question

janu16 · Answer

What do you mean by 1 is 0

anonymous · Answer

not sure. that's the way my hw has it.

janu16 · Answer

Can you take a picture

anonymous · Answer

how i typed it is how it's worded. that's why i'm having trouble

xapproachesinfinity · Answer

is 1 is zero for that poly
then $$x^3-13x^2+27x-35 ~~is~divisible~by~ (x-1) $$

anonymous · Answer

it then says " the solution set is {    }

xapproachesinfinity · Answer

zero means 1 is one of the roots
in other words one of the solutions for that equation

xapproachesinfinity · Answer

just do long division, synthetic division or what have you
to factor that equation into easy solvable factors

anonymous · Answer

i found the answer it was { 7,5,1}

anonymous · Answer

Thank you anyways

xapproachesinfinity · Answer

alright!

mathstudent55 · Answer

Divide the polynomial by x - 1 to get a quadratic. Use long division or synthetic division.
Then you can try factoring the quadratic or use the quadratic formula.

mathstudent55 · Answer

@Janu16
A zero of a polynomial equation, or a root of a polynomial equation is a solution of the equation. It is an x value at which the polynomial evaluates to zero.