Question

A typical laboratory centrifuge rotates at 4500 rpm. Test tubes have to be placed into a centrifuge very carefully because of the very large accelerations.
(a) What is the acceleration at the end of a test tube that is 8 cm from the axis of rotation?
m/s2

(b) For comparison, what is the magnitude of the acceleration a test tube would experience if dropped from a height of 1.2 m and stopped in a 1.0 ms long encounter with a hard floor?
m/s2

Answer 1

a)
Required formula is
a=omega^2*r

Answer 2

Omega=2*pi*f

Answer 3

Frequency=f=4500rpm=4500/60hz

Answer 4

A)
\[A_{c} = \frac{ V^{2} }{r }\]

B)
\[K = \frac{ 1 }{2 }MV^{2}\]

Answer 5

r=8cm=0.08m
a=?

Answer 6

R u able to do
b)