Mathematics
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OpenStudy (anonymous):
A triangle has coordinates A (1, 5), B (-2, 1) and C (0, -4). What are the new coordinates if the triangle is rotated 90° clockwise around the origin?
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OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
90 degree clockwise
is same as
270 degree counter clockwise
ganeshie8 (ganeshie8):
remember the rule for 270 degree counter clockwise rotation ?
OpenStudy (anonymous):
(A,B) (B,-A)
ganeshie8 (ganeshie8):
Yes! 270 degree counter clockwise rule is
\[(A,~~B)\longrightarrow (B, ~-A)\]
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ganeshie8 (ganeshie8):
apply it on each of the given coordinates
ganeshie8 (ganeshie8):
\[(1,~~5)\longrightarrow ?\]
OpenStudy (anonymous):
A(1,5) --> (1,-5)
B(-2,1) --> (-2,-1)
C(0,-4) --> (0,4)
ganeshie8 (ganeshie8):
not quite
you need to swap x and y coordinates
ganeshie8 (ganeshie8):
\[(1,~~5)\longrightarrow (5,~-1)\]
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ganeshie8 (ganeshie8):
see if you can work remaining two vertices
OpenStudy (anonymous):
ohh sorry i forgot..
B(-2,1) -->(1,2)
ganeshie8 (ganeshie8):
Yes!
OpenStudy (anonymous):
C(0,-4) --> (-4,-0)
ganeshie8 (ganeshie8):
Excellent! -0 is same as 0 so
\[(0,~-4)\longrightarrow (-4,~0)\]
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OpenStudy (anonymous):
ok so is that all i have to do?
ganeshie8 (ganeshie8):
yes we're done!
OpenStudy (anonymous):
ok thanks alot! :D