Question

Expand and you will get your medal :D

Answer 1

\[(2x^2 - \frac{ 1 }{ 3 }y +z)^4\]

Answer 2

using pascal or rth term

Answer 3

does it have to be using pascal's triangle?

Answer 4

nope just expand it :D

Answer 5

and show me the process :D

Answer 6

okay.. well what I would do is\[(2x^2-\frac{ 1 }{ 3 }y+z)(2x^2-\frac{ 1 }{ 3 }y+z)(2x^2-\frac{ 1 }{ 3 }y+z)(2x^2-\frac{ 1 }{ 3 }y+z)\]

Answer 7

can you simplify :D

Answer 8

then, i'd expand the first 2 then the last 2... I'm working on it xp

Answer 9

\[(4x^4-\frac{ 2 }{ 3 }x^2y+2x^2x-\frac{ 2 }{ 3 }x^2y+\frac{ 1 }{ 9 }y^2-\frac{ 1 }{ 3 }yz+2x^2z-\frac{ 1 }{ 3 }yz+z^2)^2\]

Answer 10

I'm halfway there.. sorry it's taking so long.. I'm doing my own school work as well

Answer 11

before doing the square, you should combine "like terms"
it reduces the mess, though it will still be a bit long

Answer 12

I know XD but I like doing these kind of things.

Answer 13

because i need using rth term, pascal, and the one that your doing right now :D

Answer 14

why?

Answer 15

my instructor give it as my assignment :D, but im doing many staff out here so i just post and help me to solve this

Answer 16

okay.. wow this is a long problem XD

Answer 17

i have 14 problems here like that and im working with it :D

Answer 18

haha XD I'm getting there.. I combined like terms...

Answer 19

I don't have enough room on my paper XD

Answer 20

dang it, I messed up.. sorry. :/ ummm I'm kinda dealing with things right now. and I can't help you.. sorry