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Mathematics 23 Online
OpenStudy (anonymous):

Radius of convergence. Picture will give better detail

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm unsure if i cancelled everything out as I'm unsure where to go from here

OpenStudy (anonymous):

I'm assuming sqrt(n) divided by sqrt(n+1) is just 1? but im unsure how exactly

OpenStudy (anonymous):

What test are you using? You should be more clear with your work.

OpenStudy (anonymous):

ratio test

OpenStudy (anonymous):

I thought so, please do it again.

OpenStudy (anonymous):

Is it not right as is?

OpenStudy (anonymous):

I did not check, but you should do it right, otherwise it's just a mess.

OpenStudy (anonymous):

Im pretty sure its correct. What i am left with is (x*sqrt(n))/(sqrt(n+1)*2)

OpenStudy (jtvatsim):

The ratio test requires you to take the limit as n goes to infinity

OpenStudy (anonymous):

i know, i just havent been writing the limit sign

OpenStudy (rational):

saving paper or ink ;p

OpenStudy (anonymous):

essentially all i need to know is that sqrtn divided by sqrt(n+1) is equal to 1

OpenStudy (jtvatsim):

essentially... yes

OpenStudy (jtvatsim):

so what does that leave you with if that part of the expression is 1?

OpenStudy (anonymous):

Ok can i get the proof of that? my thought is to just divide each one by sqrt(n)

OpenStudy (jtvatsim):

Sure that works

OpenStudy (anonymous):

well then its x/2 which means the radius of convergence is 2

OpenStudy (anonymous):

ok. I just wanted to make sure my thought process on the sqrt(n) part was correct

OpenStudy (jtvatsim):

Yep, your proposed proof should work as well.

OpenStudy (anonymous):

Thank you

OpenStudy (jtvatsim):

No problem! :)

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