WANT A MEDAL? Solve for x. If necessary, round your answer to the nearest hundredth.
My answer came out to 2.82 but it's not right so how do I solve this?
If I'm not mistaken, this is a 30-60-90 triangle. That means the longer leg (or x) = 2(length of the shortest leg, or 2).
wait, so x would be equal to 2 times the length of the shortest leg on the triangle?
Yep :) If this is a 30-60-90 triangle (which I'm pretty certain it is), all you need is one side length to find the other two side lengths.
Use Pythagorian theorem : x²+2²=(2sqrt(3))²
Or you could use the Pythagorean theorem like @math&ing001 suggested. Though the 30-60-90 formula is faster and simpler
\[2\sqrt{3} = 3.5\] That would be correct right? Unless because the problem says to round to the nearest hundredths then it would be \[2\sqrt{3} = 3.46\] That solves the square root part then 2 squared is 4
No, you multiplied the hypotenuse with the shortest leg. Multiply the two legs
\[x ^{2} + 4 = 3.46^{2}\] \[x ^{2} + 4 = 12\] This is how I was taught do it is that not right?
\[x ^{2} + 4 - 4 = 12 - 4\] \[x ^{2} = 8\] \[\sqrt{x ^{2}} = \sqrt{8}\] \[x = 2.82\] I think I was right....
am I right @JackofallTradez
Nope
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