Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

WANT A MEDAL? Solve for x. If necessary, round your answer to the nearest hundredth.

OpenStudy (anonymous):

OpenStudy (anonymous):

My answer came out to 2.82 but it's not right so how do I solve this?

OpenStudy (jackofalltradez):

If I'm not mistaken, this is a 30-60-90 triangle. That means the longer leg (or x) = 2(length of the shortest leg, or 2).

OpenStudy (anonymous):

wait, so x would be equal to 2 times the length of the shortest leg on the triangle?

OpenStudy (jackofalltradez):

Yep :) If this is a 30-60-90 triangle (which I'm pretty certain it is), all you need is one side length to find the other two side lengths.

OpenStudy (math&ing001):

Use Pythagorian theorem : x²+2²=(2sqrt(3))²

OpenStudy (jackofalltradez):

Or you could use the Pythagorean theorem like @math&ing001 suggested. Though the 30-60-90 formula is faster and simpler

OpenStudy (anonymous):

\[2\sqrt{3} = 3.5\] That would be correct right? Unless because the problem says to round to the nearest hundredths then it would be \[2\sqrt{3} = 3.46\] That solves the square root part then 2 squared is 4

OpenStudy (jackofalltradez):

No, you multiplied the hypotenuse with the shortest leg. Multiply the two legs

OpenStudy (anonymous):

\[x ^{2} + 4 = 3.46^{2}\] \[x ^{2} + 4 = 12\] This is how I was taught do it is that not right?

OpenStudy (jackofalltradez):

OpenStudy (anonymous):

\[x ^{2} + 4 - 4 = 12 - 4\] \[x ^{2} = 8\] \[\sqrt{x ^{2}} = \sqrt{8}\] \[x = 2.82\] I think I was right....

OpenStudy (anonymous):

am I right @JackofallTradez

OpenStudy (jackofalltradez):

Nope

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!