Question

DC Circuit Question

Answer 1

a circuit where R1 = 5.50 Ω, R2 = 5.00 Ω, R3 = 1.30 Ω, V1 = 32.40 V, V2 = 32.40 V, and V3 = 36.00 V.

I know I have to use Kirchoff's Rules but I think my 3 equations might be incorrect if anyone could give them a quick once over.

\[I _{1} + I _{2} + I _{3} = 0\]
\[V _{1} +I_{1}R{1} -I_{3}R_{3} +V_{3} = 0 \]
\[V_{2}+I_{2}R_{2}-I_{1}R_{1} - V_{1} =0\]

Answer 2

first equation is wrong

Answer 3

Remember, Currents going into a junction = currents going out of a junction

Answer 4

So it's

\[I_{1} + I_{3} = I_{2}\]

Answer 5

Actually taking a second look at it I think you are correct
I1 = -I2 -I 3

Answer 6

which way did you loop couter or clock wise

Answer 7

Clockwise

Answer 8

Hw first equation is wrong??!!!! @Austin6i6

Answer 9

if you could read @shamim you would see i corrected my self

Answer 10

yeah looks good @Alessandro92

Answer 11

I saw all the three current i1,i2,i3 r directed to one point. So according to chirchoff's law
i1+i2+i3=0
Right?

Answer 12

C the drawing of circuit plz!!!

Answer 13

yes that is right

Answer 14

Assumption of direction of current is not correct

Answer 15

So we will get correct direction after all calculation

Answer 16

Alright so my first equation is fine I'm assuming.
And no complaints over the last two?

Answer 17

For example if we get i2=-4Amp

Answer 18

Then we will conclude our assumption of direction of i2 was wrong!!!

Answer 19

Yes I know , if we get a negative it simply means current is moving in the opposite direction which we assumed

Answer 20

Direction of i2 is just oposit of our assumption direction